用python制作剪刀石头布游戏

1、由于需要电脑随机出拳，所以我们这里导入随机数模块，具体代码：import random然后用input 代码和用户交互，让用户选择出 剪刀 石头或者布player = input("请输入要出的选项:剪刀(1)/石头(2)/布(3)")

2、对玩家出拳进行判断，我们这里用 1 代表了 剪刀 2 代表石头 3 代表布 所以我们限制玩家只能出 这三个数字，输入其他字符 则提示玩家出拳错误if player.isdigit() and int(player) >= 1 and int(player) <= 3:else: print("出拳有误")

3、下面在用户输入正确的情况下 写入判断代码，首先把用户输入的数字转换成整数类型，以及将电脑随机数代码完善player = int(player)cpu = random.randint(1, 3)

4、继续用if判断，将电脑和用户输入的数字判断成拳头，代码如下：if player 屏顿幂垂== 1: player1 = "稆糨孝汶;剪刀"if player == 2: player1 = "石头"if player == 3: player1 = "布"if cpu == 1: cpu1 = "剪刀"if cpu == 2: cpu1 = "石头"if cpu == 3: cpu1 = "布"print("玩家出拳为:", player1, "电脑出拳为:", cpu1)判断最后打印出双方出拳的结果

5、然后我们进行胜负条件的判断，我们先写上当用户胜利时候的情况，具体代码如下：if (player == 1 and cpu == 3) \ or (player == 2 and cpu == 1) \ or (player == 3 and cpu == 2): print("玩家胜利")

6、按照同样的判断方法，幼榍嘈酾判断出电脑胜利和平局的结果：if (player == 1 and cpu == 2) \ or (player == 2 and cpu == 3) \ or (player == 3 and cpu == 1): print("电脑胜利")if (player == 1 and cpu == 1) \ or (player == 2 and cpu == 2) \ or (player == 3 and cpu == 3): print("平局")

7、经过以上代码，我们基本完成了整个游戏的过程，下面运行一下看效果：

8、整体代码总结：import randomplayer = input("请输入要出的选项:剪刀(1)/石头(2)/布(3)")if player.isdigit() and int(player) >= 1 and int(player) <= 3: player = int(player) cpu = random.randint(1, 3) if player == 1: player1 = "剪刀" if player == 2: player1 = "石头" if player == 3: player1 = "布" if cpu == 1: cpu1 = "剪刀" if cpu == 2: cpu1 = "石头" if cpu == 3: cpu1 = "布" print("玩家出拳为:", player1, "电脑出拳为:", cpu1)# if (player == 1 and cpu == 3) \ or (player == 2 and cpu == 1) \ or (player == 3 and cpu == 2): print("玩家胜利") if (player == 1 and cpu == 2) \ or (player == 2 and cpu == 3) \ or (player == 3 and cpu == 1): print("电脑胜利") if (player == 1 and cpu == 1) \ or (player == 2 and cpu == 2) \ or (player == 3 and cpu == 3): print("平局")else: print("出拳有误")